What is the critical f(x)=x^3-2xy+y^2+4 ?

The critical f(x)=x^3-2xy+y^2+4 is (2/3 , 2/3),(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=x^3-2xy+y^2+4

critical points

f (x) = x^{3} - 2 x y + y^{2} + 4

(\frac{2}{3}, \frac{2}{3}), (0, 0)

Solution steps

x^{3} - 2 x y + y^{2} + 4

Find where

\nabla f (x, y)

is equal to zero or undefined

(\frac{2}{3}, \frac{2}{3}), (0, 0)

- 2 x^{2} - 12 x - 13

f (x, y) = x^{3} + y^{3} - 2 x y

f (x) = 8 x^{2} + 14 x y + 3 y^{2} + 10 x - 4

f (x) = 2 x^{3} + 6 x^{2} - 5

f (x) = sin (x) + cos (x), 0 \leq x \leq 2 π

What is the critical f(x)=x^3-2xy+y^2+4 ?
The critical f(x)=x^3-2xy+y^2+4 is (2/3 , 2/3),(0,0)