What is the extreme f(x)=-4x^2-4,-5<= x<= 4 ?

The extreme f(x)=-4x^2-4,-5<= x<= 4 is Minimum(-5,-104),Maximum(0,-4),Minimum(4,-68)

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extreme f(x)=-4x^2-4,-5<= x<= 4

extreme points

f (x) = - 4 x^{2} - 4, - 5 \leq x \leq 4

Minimum (- 5, - 104), Maximum (0, - 4), Minimum (4, - 68)

Solution steps

Find the critical points:

x = - 5, x = 0, x = 4

Domain of

- 4 x^{2} - 4, - 5 \leq x \leq 4 : - 5 \leq x \leq 4

Find intervals:

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 4

Plug the extreme point

x = - 5

into

- 4 x^{2} - 4 \Rightarrow y = - 104

Minimum (- 5, - 104)

Plug the extreme point

x = 0

into

- 4 x^{2} - 4 \Rightarrow y = - 4

Maximum (0, - 4)

Plug the extreme point

x = 4

into

- 4 x^{2} - 4 \Rightarrow y = - 68

Minimum (4, - 68)

Minimum (- 5, - 104), Maximum (0, - 4), Minimum (4, - 68)

f (x) = 3 x^{3} - 2

y = - 2 x + 3

f (x) = \frac{- 2 x + 1}{x - 5}

f (x) = \frac{4 x - 9}{x - 4}

- x^{2} - 3

What is the extreme f(x)=-4x^2-4,-5<= x<= 4 ?
The extreme f(x)=-4x^2-4,-5<= x<= 4 is Minimum(-5,-104),Maximum(0,-4),Minimum(4,-68)