What is the critical f(x)=-2csc(3x+pi)-1 ?

The critical f(x)=-2csc(3x+pi)-1 is x= pi/6+(2pi)/3 n,x= pi/2+(2pi)/3 n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=-2csc(3x+pi)-1

critical points

f (x) = - 2 csc (3 x + π) - 1

x = \frac{π}{6} + \frac{2 π}{3} n, x = \frac{π}{2} + \frac{2 π}{3} n

Solution steps

- 2 csc (3 x + π) - 1

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{6} + \frac{2 π}{3} n, x = \frac{π}{2} + \frac{2 π}{3} n, x = \frac{2 π}{3} n, x = \frac{π}{3} + \frac{2 π}{3} n

Identify critical points not in

f (x)

domain

Domain of

- 2 csc (3 x + π) - 1 : \frac{2 π}{3} n < x < \frac{π}{3} + \frac{2 π}{3} n or \frac{π}{3} + \frac{2 π}{3} n < x < \frac{2 π}{3} + \frac{2 π}{3} n

- 2 csc (3 x + π) - 1

is not defined at

x = \frac{2 π}{3} n, x = \frac{π}{3} + \frac{2 π}{3} n

, therefore:

x = \frac{π}{6} + \frac{2 π}{3} n, x = \frac{π}{2} + \frac{2 π}{3} n

f (x) = \frac{x}{( 1 + x ^{2} )}

sin^{2} (x) - cos (x)

f (x) = sin (x) - x

f (x) = x^{2} - 16 x^{4}

x^{2} + x y + y^{2} + 3 x - 3 y + 4

What is the critical f(x)=-2csc(3x+pi)-1 ?
The critical f(x)=-2csc(3x+pi)-1 is x= pi/6+(2pi)/3 n,x= pi/2+(2pi)/3 n