What is the critical f(x)=6x^3-15x^2+12x-6 ?

The critical f(x)=6x^3-15x^2+12x-6 is x= 2/3 ,x=1

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critical f(x)=6x^3-15x^2+12x-6

critical points

f (x) = 6 x^{3} - 15 x^{2} + 12 x - 6

x = \frac{2}{3}, x = 1

Solution steps

6 x^{3} - 15 x^{2} + 12 x - 6

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{2}{3}, x = 1

Identify critical points not in

f (x)

domain

Domain of

6 x^{3} - 15 x^{2} + 12 x - 6 : - \infty < x < \infty

All critical points are in domain

x = \frac{2}{3}, x = 1

f (x, y) = e^{y} - y e^{x}

f (x, y) = \frac{x}{y} + \frac{8}{x} - y

f (x) = 5

2 z^{4} - 16 z^{3} + 20 z^{2} - 7

x^{3} y^{3} - 3 x y

What is the critical f(x)=6x^3-15x^2+12x-6 ?
The critical f(x)=6x^3-15x^2+12x-6 is x= 2/3 ,x=1