What is the critical f(x)=(x^2-4x)/((x-2)^2) ?

The critical f(x)=(x^2-4x)/((x-2)^2) is None

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critical f(x)=(x^2-4x)/((x-2)^2)

critical points

f (x) = \frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

None

Solution steps

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}} : x < 2 or x > 2

\frac{x ^{2} - 4 x}{( x - 2 ) ^{2}}

is not defined at

x = 2

, therefore:

None

f (x) = x^{2} e^{6 x}

f (x) = 2 x - 3

f (x) = 3 x^{3} + 9 x^{2} - 72 x

f (x, y) = 2 x^{2} + 2 y^{2} - x^{4} - y^{4} + 3

f (x, y) = 3 x^{3} + y^{2} - 9 x + 4 y

What is the critical f(x)=(x^2-4x)/((x-2)^2) ?
The critical f(x)=(x^2-4x)/((x-2)^2) is None