What is the critical f(x)=e^{4x}(32x^2+2) ?

The critical f(x)=e^{4x}(32x^2+2) is x=-1/4

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critical f(x)=e^{4x}(32x^2+2)

critical points

f (x) = e^{4 x} (32 x^{2} + 2)

x = - \frac{1}{4}

Solution steps

e^{4 x} (32 x^{2} + 2)

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{4}

Identify critical points not in

f (x)

domain

Domain of

e^{4 x} (32 x^{2} + 2) : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{4}

f (x, y) = x^{2} + 4 y^{2} + y^{3} + 4 x

x^{3} + 6 x^{2} + 9 x

x + \frac{64}{x}

f (x) = 5 sin (x) cos (x), (0, 2 π)

f (x, y) = x y - x^{2} y - x y^{2}

What is the critical f(x)=e^{4x}(32x^2+2) ?
The critical f(x)=e^{4x}(32x^2+2) is x=-1/4