What is the critical f(x)=((x+1)^3)/((x-1)^2) ?

The critical f(x)=((x+1)^3)/((x-1)^2) is x=-1,x=5

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critical f(x)=((x+1)^3)/((x-1)^2)

critical points

f (x) = \frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

x = - 1, x = 5

Solution steps

\frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 5, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}} : x < 1 or x > 1

\frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

is not defined at

x = 1

, therefore:

x = - 1, x = 5

f (x) = 3 x^{2} - x^{3}

f (x) = (x^{2} - 1)^{6}

f (x, y) = x^{3} - 2 y^{2} - 2 y^{4} + 3 x^{2} y

f (x) = x^{2} (x - 12)^{2}

f (x) = sin^{2} (6 x) + cos (6 x)

What is the critical f(x)=((x+1)^3)/((x-1)^2) ?
The critical f(x)=((x+1)^3)/((x-1)^2) is x=-1,x=5