What is the critical f(x)=(3x)/(x^2-36) ?

The critical f(x)=(3x)/(x^2-36) is None

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critical f(x)=(3x)/(x^2-36)

critical points

f (x) = \frac{3 x}{x ^{2} - 36}

None

Solution steps

\frac{3 x}{x ^{2} - 36}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6, x = 6

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x}{x ^{2} - 36} : x < - 6 or - 6 < x < 6 or x > 6

\frac{3 x}{x ^{2} - 36}

is not defined at

x = - 6, x = 6

, therefore:

None

f (x, y) = 2 x^{3} - 6 x^{2} + y^{3} + 21 y^{2}

x - 2 cos (x)

f (x) = cos (x) + \frac{3}{2} x

f (x) = x^{3} - 6 x^{2} + 12 x - 8

f (x, y) = x^{3} + y^{3} - 12 x y

What is the critical f(x)=(3x)/(x^2-36) ?
The critical f(x)=(3x)/(x^2-36) is None