What is the critical f(x)=(x^2-4)/(x-1) ?

The critical f(x)=(x^2-4)/(x-1) is None

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critical f(x)=(x^2-4)/(x-1)

critical points

f (x) = \frac{x ^{2} - 4}{x - 1}

None

Solution steps

\frac{x ^{2} - 4}{x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 4}{x - 1} : x < 1 or x > 1

\frac{x ^{2} - 4}{x - 1}

is not defined at

x = 1

, therefore:

None

f (x) = x (x + 7) (x - 5)

5 x^{4} - 20 x^{3} + 9

x - 2 x

f (x, y) = 10 - 8 x + 5 y + 3 x^{2} - 7 x y + 2 y^{2}

f (x) = 3 x^{3} - 2 x

What is the critical f(x)=(x^2-4)/(x-1) ?
The critical f(x)=(x^2-4)/(x-1) is None