What is the critical f(x)=((x^2+2))/(2x-1) ?

The critical f(x)=((x^2+2))/(2x-1) is x=-1,x=2

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critical f(x)=((x^2+2))/(2x-1)

critical points

f (x) = \frac{( x ^{2} + 2 )}{2 x - 1}

x = - 1, x = 2

Solution steps

\frac{x ^{2} + 2}{2 x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 2}{2 x - 1} : x < \frac{1}{2} or x > \frac{1}{2}

\frac{x ^{2} + 2}{2 x - 1}

is not defined at

x = \frac{1}{2}

, therefore:

x = - 1, x = 2

f (x) = 2 x^{2} + y^{2} + 3 x y - 3 y - 5 x + 8

\frac{5 x}{x ^{2} - 25}

\frac{( x ^{2} )}{x - 2}

f (x, y) = \frac{3 x ^{2} + 1}{2} - x (x^{2} + y^{2})

f (x) = 25 x - 2 x^{2} - 3 y^{2} + 3 x y

What is the critical f(x)=((x^2+2))/(2x-1) ?
The critical f(x)=((x^2+2))/(2x-1) is x=-1,x=2