What is the critical f(x)=x^3+3/x ?

The critical f(x)=x^3+3/x is x=-1,x=1

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critical f(x)=x^3+3/x

critical points

f (x) = x^{3} + \frac{3}{x}

x = - 1, x = 1

Solution steps

x^{3} + \frac{3}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{3} + \frac{3}{x} : x < 0 or x > 0

x^{3} + \frac{3}{x}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

f (x) = x^{3} + x - 1

f (x) = \frac{2 x + 3}{x + 2}

x x - x^{2}

(x^{2} + y^{2}) e^{y^{2} - x^{2}}

\frac{4 x}{x ^{2} - 4}