What is the critical f(x)=(1-2ln(x))/(x^3) ?

The critical f(x)=(1-2ln(x))/(x^3) is x=e^{5/6}

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critical f(x)=(1-2ln(x))/(x^3)

critical points

f (x) = \frac{1 - 2 ln ( x )}{x ^{3}}

x = e^{\frac{5}{6}}

Solution steps

\frac{1 - 2 ln ( x )}{x ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = e^{\frac{5}{6}}, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{1 - 2 ln ( x )}{x ^{3}} : x > 0

\frac{1 - 2 ln ( x )}{x ^{3}}

is not defined at

x = 0

, therefore:

x = e^{\frac{5}{6}}

y = I n^{2} (x^{2} - x)

x^{2} - 2 x - 1

f (x, y) = x y + \frac{9}{x} + \frac{3}{y}

f (x) = x^{2} + 4 x + 2

f (x) = x^{4} - 4 x^{3} - 18 x^{2}

What is the critical f(x)=(1-2ln(x))/(x^3) ?
The critical f(x)=(1-2ln(x))/(x^3) is x=e^{5/6}