What is the critical y= x/(4-x^2) ?

The critical y= x/(4-x^2) is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical y= x/(4-x^2)

critical points

y = \frac{x}{4 - x ^{2}}

None

Solution steps

\frac{x}{4 - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{4 - x ^{2}} : x < - 2 or - 2 < x < 2 or x > 2

\frac{x}{4 - x ^{2}}

is not defined at

x = - 2, x = 2

, therefore:

None

\frac{x + 1}{x ^{2} + 3}

f (x) = x^{3} + x^{2} - 5 x - 5

f (x) = x + \frac{32}{x}

f (x) = x 2 - x^{2}

f (x) = \frac{2}{x - 3}