What is the critical-9/((x^2-9)sqrt(x^2-9)) ?

The critical-9/((x^2-9)sqrt(x^2-9)) is None

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critical-9/((x^2-9)sqrt(x^2-9))

critical points

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9}

None

Solution steps

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9} : x < - 3 or x > 3

- \frac{9}{( x ^{2} - 9 ) x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

None

\frac{2 x}{3 ( x ^{2} - 1 ) ^{\frac{2}{3}}}

f (x) = e^{x^{2} - 5 x - 1}

1 + 6 x^{2} - x^{3}

4 x^{2} + 4 y^{2} + x^{4} + y^{4} - 6 x^{2} y^{2}

y = x^{\frac{4}{7}} (x^{2} - 6)

What is the critical-9/((x^2-9)sqrt(x^2-9)) ?
The critical-9/((x^2-9)sqrt(x^2-9)) is None