What is the critical f(x,y)=3(2x^2-3y^3)^4 ?

The critical f(x,y)=3(2x^2-3y^3)^4 is (0,0)

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critical f(x,y)=3(2x^2-3y^3)^4

critical points

f (x, y) = 3 (2 x^{2} - 3 y^{3})^{4}

(0, 0)

Solution steps

3 (2 x^{2} - 3 y^{3})^{4}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0)

\frac{x ^{7} - 4 x ^{6} - 16 x ^{5} + 64 x ^{4}}{x}

f (x) = x^{(4)} - 4 x^{(2)}

x + 1 - x

f (x) = \frac{4 e ^{x}}{4 e ^{x} + 5}

\frac{4 x ^{2}}{x ^{2} - 4}

What is the critical f(x,y)=3(2x^2-3y^3)^4 ?
The critical f(x,y)=3(2x^2-3y^3)^4 is (0,0)