What is the critical 2x^3+9x^2+12x+1 ?

The critical 2x^3+9x^2+12x+1 is x=-2,x=-1

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critical 2x^3+9x^2+12x+1

critical points

2 x^{3} + 9 x^{2} + 12 x + 1

x = - 2, x = - 1

Solution steps

2 x^{3} + 9 x^{2} + 12 x + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = - 1

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} + 9 x^{2} + 12 x + 1 : - \infty < x < \infty

All critical points are in domain

x = - 2, x = - 1

\frac{x ^{2} - x + 1}{x - 1}

lo g_{4} (x)

6 x^{2} - 6 x - 72

f (x) = \frac{2 x}{1 + x ^{2}}

f (x, y) = x^{2} + y^{2} - x y + x^{3}

What is the critical 2x^3+9x^2+12x+1 ?
The critical 2x^3+9x^2+12x+1 is x=-2,x=-1