What is the critical f(x)= x/(x^2+13x+42) ?

The critical f(x)= x/(x^2+13x+42) is x=-sqrt(42),x=sqrt(42)

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critical f(x)= x/(x^2+13x+42)

critical points

f (x) = \frac{x}{x ^{2} + 13 x + 42}

x = - 42, x = 42

Solution steps

\frac{x}{x ^{2} + 13 x + 42}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 42, x = 42, x = - 7, x = - 6

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 13 x + 42} : x < - 7 or - 7 < x < - 6 or x > - 6

\frac{x}{x ^{2} + 13 x + 42}

is not defined at

x = - 7, x = - 6

, therefore:

x = - 42, x = 42

\frac{2 x ^{2} - 2}{x ^{2} - 4}

a x^{2} + 2 x y + 3 y^{2} + 4 x - 1

f (x) = \frac{x ^{3}}{3} + \frac{3 x ^{2}}{2} - 10 x - 1

f (x) = I n (3 - 2 x)

x e^{- 4 x}

What is the critical f(x)= x/(x^2+13x+42) ?
The critical f(x)= x/(x^2+13x+42) is x=-sqrt(42),x=sqrt(42)