What is the critical f(x)=xe^{3x} ?

The critical f(x)=xe^{3x} is x=-1/3

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critical f(x)=xe^{3x}

critical points

f (x) = x e^{3 x}

x = - \frac{1}{3}

Solution steps

x e^{3 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

x e^{3 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{3}

(1, 5), (3, 6)

f (x) = 4 - x^{2} - x + 1

2 x - y = 5

f (t) = \frac{4}{t}

f (x) = \frac{x - 2}{3 x + 5}