What is the critical f(x,y)=(1-x^2)^2-y^2 ?

The critical f(x,y)=(1-x^2)^2-y^2 is (0,0),(-1,0),(1,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x,y)=(1-x^2)^2-y^2

critical points

f (x, y) = (1 - x^{2})^{2} - y^{2}

(0, 0), (- 1, 0), (1, 0)

Solution steps

(1 - x^{2})^{2} - y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (- 1, 0), (1, 0)

f (x) = (x^{2})

f (x, y) = x^{2} y - y^{3} - x^{2} - y^{2} + 1

f (x) = \frac{2}{3} x^{\frac{3}{2}} - \frac{2}{5} x^{\frac{5}{2}}

f (x) = 3 x^{\frac{1}{2}} - x^{\frac{3}{2}}

f (x) = x^{2} + \frac{54}{x}

What is the critical f(x,y)=(1-x^2)^2-y^2 ?
The critical f(x,y)=(1-x^2)^2-y^2 is (0,0),(-1,0),(1,0)