What is the critical f(x)=(x^2-5x+6)/(x^2) ?

The critical f(x)=(x^2-5x+6)/(x^2) is x= 12/5

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critical f(x)=(x^2-5x+6)/(x^2)

critical points

f (x) = \frac{x ^{2} - 5 x + 6}{x ^{2}}

x = \frac{12}{5}

Solution steps

\frac{x ^{2} - 5 x + 6}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{12}{5}, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 5 x + 6}{x ^{2}} : x < 0 or x > 0

\frac{x ^{2} - 5 x + 6}{x ^{2}}

is not defined at

x = 0

, therefore:

x = \frac{12}{5}

y = 3 x^{4} + 4 x^{3} - 12 x^{2}

f (x) = (\frac{x ^{3} + 1}{x ^{2} - 1})

f (x) = 4 x^{3} + 3 x^{2} - 6 x

f (x) = 6 x^{5} - 90 x^{3}

f (x) = 5 x^{\frac{2}{3}} + x^{\frac{5}{3}}

What is the critical f(x)=(x^2-5x+6)/(x^2) ?
The critical f(x)=(x^2-5x+6)/(x^2) is x= 12/5