What is the critical f(x)=(x^3)/3+(x^2)/2-2x ?

The critical f(x)=(x^3)/3+(x^2)/2-2x is x=-2,x=1

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critical f(x)=(x^3)/3+(x^2)/2-2x

critical points

f (x) = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x

x = - 2, x = 1

Solution steps

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 1

∣ sin (x) ∣

f (x) = x^{4} - 8 x + 10

f (x) = \frac{6}{x + 2}

f (x) = 3 x^{2} - 4 x + 5

f (x) = 2 x^{3} + 6 x^{2} - 18 x + 1

What is the critical f(x)=(x^3)/3+(x^2)/2-2x ?
The critical f(x)=(x^3)/3+(x^2)/2-2x is x=-2,x=1