What is the critical f(x,y)=x^3+xy+y^2 ?

The critical f(x,y)=x^3+xy+y^2 is (0,0),(1/6 ,-1/12)

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critical f(x,y)=x^3+xy+y^2

critical points

f (x, y) = x^{3} + x y + y^{2}

(0, 0), (\frac{1}{6}, - \frac{1}{12})

Solution steps

x^{3} + x y + y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (\frac{1}{6}, - \frac{1}{12})

f (x) = 4 x + sin (4 x)

f (x, y) = - 4 x y + x^{4} + y^{4}

f (x) = x^{\frac{4}{5}} (9 x - 36)^{2}

f (x) = x^{2} - 3 x + 2

x x^{2} + 36

What is the critical f(x,y)=x^3+xy+y^2 ?
The critical f(x,y)=x^3+xy+y^2 is (0,0),(1/6 ,-1/12)