What is the critical f(x)=(x^2)/(1-x^3) ?

The critical f(x)=(x^2)/(1-x^3) is x=-\sqrt[3]{2},x=0

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critical f(x)=(x^2)/(1-x^3)

critical points

f (x) = \frac{x ^{2}}{1 - x ^{3}}

Solution steps

\frac{x ^{2}}{1 - x ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{1 - x ^{3}} : x < 1 or x > 1

\frac{x ^{2}}{1 - x ^{3}}

is not defined at

x = 1

, therefore:

y = 4 x^{3} - x^{4}

x^{2} - 3 x y - y^{2}

f (x) = 9 x + \frac{1}{x}

f (x) = x^{2} - 25

f (x, y) = x^{2} e^{y}

What is the critical f(x)=(x^2)/(1-x^3) ?
The critical f(x)=(x^2)/(1-x^3) is x=-\sqrt[3]{2},x=0