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Popular >

distance (6,5),(-2,5)

Solution

distance

(6, 5), (- 2, 5)

Solution

8

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(6, 5)

and

(- 2, 5)

is

= (- 2 - 6)^{2} + (5 - 5)^{2}

Simplify

= 8

Popular Examples

critical x^2-2x+7 critical points

x^{2} - 2 x + 7

domain of f(x)=(2x-2)/(x^2-x)-4 domain

f (x) = \frac{2 x - 2}{x ^{2} - x} - 4

critical f(x)=(x+8)^8 critical points

f (x) = (x + 8)^{8}

range of f(x)=-x^2-5 range

f (x) = - x^{2} - 5

domain of (1-9sqrt(x))/x domain

\frac{1 - 9 x}{x}

Frequently Asked Questions (FAQ)

What is the distance (6,5),(-2,5) ?
The distance (6,5),(-2,5) is 8