What is the critical f(x)=(x-1)/(x^2-1) ?

The critical f(x)=(x-1)/(x^2-1) is None

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critical f(x)=(x-1)/(x^2-1)

critical points

f (x) = \frac{x - 1}{x ^{2} - 1}

None

Solution steps

\frac{x - 1}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 1}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

\frac{x - 1}{x ^{2} - 1}

is not defined at

x = - 1

, therefore:

None

f (x) = (x^{2} - 1)^{\frac{2}{3}}

f (x) = sin (x + \frac{π}{4})

(4 x - 3)^{\frac{1}{3}}

f (x) = \frac{4 x}{x ^{2} - 36}

x^{3} - 9 x

What is the critical f(x)=(x-1)/(x^2-1) ?
The critical f(x)=(x-1)/(x^2-1) is None