What is the critical (2x^2-3x)/(x-2) ?

The critical (2x^2-3x)/(x-2) is x=1,x=3

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critical (2x^2-3x)/(x-2)

critical points

\frac{2 x ^{2} - 3 x}{x - 2}

x = 1, x = 3

Solution steps

\frac{2 x ^{2} - 3 x}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 3, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x ^{2} - 3 x}{x - 2} : x < 2 or x > 2

\frac{2 x ^{2} - 3 x}{x - 2}

is not defined at

x = 2

, therefore:

x = 1, x = 3

f (x, y) = (x^{2} - 1) y

f (x) = 36 x^{3} - 11 x

f (x) = \frac{x ^{3}}{3} - 2 x^{2} - 5 x

y^{2} - y

f (x, y) = - 384 x + 2 x^{3} + 6 x y^{2} - 3 y^{3}