What is the critical f(x,y)=6xy-4x^3-3y^2 ?

The critical f(x,y)=6xy-4x^3-3y^2 is (0,0),(1/2 , 1/2)

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critical f(x,y)=6xy-4x^3-3y^2

critical points

f (x, y) = 6 x y - 4 x^{3} - 3 y^{2}

(0, 0), (\frac{1}{2}, \frac{1}{2})

Solution steps

6 x y - 4 x^{3} - 3 y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (\frac{1}{2}, \frac{1}{2})

\frac{x + 3}{x + 9}

f (x) = x^{\frac{3}{5}} (x - 3)

x^{2} y + y^{3} - 48 y

g (x) = x - e^{3 x}

y = 2 x^{3} + 3 x^{2} - 12 x

What is the critical f(x,y)=6xy-4x^3-3y^2 ?
The critical f(x,y)=6xy-4x^3-3y^2 is (0,0),(1/2 , 1/2)