What is the critical f(x,y)=xy+ln(x)+18y^2 ?

The critical f(x,y)=xy+ln(x)+18y^2 is (-6, 1/6),(6,-1/6)

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critical f(x,y)=xy+ln(x)+18y^2

critical points

f (x, y) = x y + ln (x) + 18 y^{2}

(- 6, \frac{1}{6}), (6, - \frac{1}{6})

Solution steps

x y + ln (x) + 18 y^{2}

Find where

\nabla f (x, y)

is equal to zero or undefined

(- 6, \frac{1}{6}), (6, - \frac{1}{6})

f (x) = - 3 x^{2} - 4 x - 2

f (x) = \frac{6 x ^{2}}{x ^{2} - 16}

f (x) = x^{3} - 3 x y^{2} + y^{3}

f (x, y) = x^{3} + y^{3} - 9 x y

f (x) = 4 x^{3} + 12 x^{2}

What is the critical f(x,y)=xy+ln(x)+18y^2 ?
The critical f(x,y)=xy+ln(x)+18y^2 is (-6, 1/6),(6,-1/6)