What is the critical f(x)=(x^2)/(sqrt(x^2-1)) ?

The critical f(x)=(x^2)/(sqrt(x^2-1)) is x=-sqrt(2),x=sqrt(2)

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critical f(x)=(x^2)/(sqrt(x^2-1))

critical points

f (x) = \frac{x ^{2}}{x ^{2} - 1}

x = - 2, x = 2

Solution steps

\frac{x ^{2}}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x ^{2} - 1} : x < - 1 or x > 1

\frac{x ^{2}}{x ^{2} - 1}

is not defined at

x = - 1, x = 1

, therefore:

x = - 2, x = 2

3 x^{2} - 6 x

f (x, y) = x^{2} - y - ln (x y)

f (x) = \frac{2 x - 1}{x + 2}

3 x^{2} y + y^{3} - 3 x^{2} - 3 y^{2} + 2

\frac{4 x ^{2} + 1}{x ^{2} + x + 16}

What is the critical f(x)=(x^2)/(sqrt(x^2-1)) ?
The critical f(x)=(x^2)/(sqrt(x^2-1)) is x=-sqrt(2),x=sqrt(2)