What is the critical (x^2-2x+4)/((x-1)^2) ?

The critical (x^2-2x+4)/((x-1)^2) is None

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critical (x^2-2x+4)/((x-1)^2)

critical points

\frac{x ^{2} - 2 x + 4}{( x - 1 ) ^{2}}

None

Solution steps

\frac{x ^{2} - 2 x + 4}{( x - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x + 4}{( x - 1 ) ^{2}} : x < 1 or x > 1

\frac{x ^{2} - 2 x + 4}{( x - 1 ) ^{2}}

is not defined at

x = 1

, therefore:

None

2 x^{2} + 4 x - 6

p (x) = x^{3} - a^{2} x

f (x) = \frac{( x ^{2} + 5 x + 4 )}{x ^{2}}

2 x^{2} + 4 x + 6

f (x) = a x^{2} + 2 x y + 3 y^{2} + 4 x - 1

What is the critical (x^2-2x+4)/((x-1)^2) ?
The critical (x^2-2x+4)/((x-1)^2) is None