What is the critical f(x)=(x^2)/(3x-6) ?

The critical f(x)=(x^2)/(3x-6) is x=0,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=(x^2)/(3x-6)

critical points

f (x) = \frac{x ^{2}}{3 x - 6}

x = 0, x = 4

Solution steps

\frac{x ^{2}}{3 x - 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{3 x - 6} : x < 2 or x > 2

\frac{x ^{2}}{3 x - 6}

is not defined at

x = 2

, therefore:

x = 0, x = 4

f (x) = - x^{3} - 11 x^{2} - 35 x - 29

f (x) = x^{3} - 8

f (x) = x^{3} - 15 x^{2} + 72 - 100

x^{2} - x - 2

f (x) = x^{4} - 8 x^{2} + 7

What is the critical f(x)=(x^2)/(3x-6) ?
The critical f(x)=(x^2)/(3x-6) is x=0,x=4