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Popular >

range of-x^2+2x-1

Solution

range

- x^{2} + 2 x - 1

Solution

f (x) \leq 0

+1

Interval Notation

(- \infty, 0]

Solution steps

Vertex of

- x^{2} + 2 x - 1 :

Maximum

(1, 0)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (1, 0)

f (x) \leq 0

Popular Examples

midpoint (-1,1),(-2,-1)midpoint

(- 1, 1), (- 2, - 1)

critical 6x-x^2-5 critical points

6 x - x^{2} - 5

domain of f(x)=e^{-t}domain

f (x) = e^{- t}

inverse of x^2-8x+12 inverse

x^{2} - 8 x + 12

inverse of x^2+10x+25 inverse

x^{2} + 10 x + 25

Frequently Asked Questions (FAQ)

What is the range of-x^2+2x-1 ?
The range of-x^2+2x-1 is f(x)<= 0