What is the critical-4x^3+18x^2-18x ?

The critical-4x^3+18x^2-18x is x=(3-sqrt(3))/2 ,x=(3+sqrt(3))/2

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critical-4x^3+18x^2-18x

critical points

- 4 x^{3} + 18 x^{2} - 18 x

x = \frac{3 - 3}{2}, x = \frac{3 + 3}{2}

Solution steps

- 4 x^{3} + 18 x^{2} - 18 x

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3 - 3}{2}, x = \frac{3 + 3}{2}

Identify critical points not in

f (x)

domain

Domain of

- 4 x^{3} + 18 x^{2} - 18 x : - \infty < x < \infty

All critical points are in domain

x = \frac{3 - 3}{2}, x = \frac{3 + 3}{2}

f (x) = \frac{e ^{x} + e ^{- x}}{6}

f (x, y) = x^{4} - y^{2} + 32 x + 5

f (x) = 4 x + 6 y - x^{2} - y^{2}

f (x) = \frac{( 2 x - 1 )}{( x - 1 )}

ln (8 + x^{3})

What is the critical-4x^3+18x^2-18x ?
The critical-4x^3+18x^2-18x is x=(3-sqrt(3))/2 ,x=(3+sqrt(3))/2