What is the critical f(x)=(x^2-2x)/((x-1)^2) ?

The critical f(x)=(x^2-2x)/((x-1)^2) is None

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critical f(x)=(x^2-2x)/((x-1)^2)

critical points

f (x) = \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

None

Solution steps

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}} : x < 1 or x > 1

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

is not defined at

x = 1

, therefore:

None

f (x) = 4 x^{3} + 7 x^{2} - 6 x - 3

f (x) = x^{3} - 3 x

f (- 4) = x^{2} + 4 x + 4

(x - 1)^{3}

x^{2} + 6 x y + 12 y^{2} - 6 x + 10 y - 2

What is the critical f(x)=(x^2-2x)/((x-1)^2) ?
The critical f(x)=(x^2-2x)/((x-1)^2) is None