What is the critical f(x)=((x-1)^{2/3})/(x^2) ?

The critical f(x)=((x-1)^{2/3})/(x^2) is x=1,x= 3/2

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critical f(x)=((x-1)^{2/3})/(x^2)

critical points

f (x) = \frac{( x - 1 ) ^{\frac{2}{3}}}{x ^{2}}

x = 1, x = \frac{3}{2}

Solution steps

\frac{( x - 1 ) ^{\frac{2}{3}}}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3}{2}, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{( x - 1 ) ^{\frac{2}{3}}}{x ^{2}} : x < 0 or x > 0

\frac{( x - 1 ) ^{\frac{2}{3}}}{x ^{2}}

is not defined at

x = 0

, therefore:

x = 1, x = \frac{3}{2}

x^{2} + 2 y^{2} - x^{2} y

x^{3} - 6 x^{2} - 15 x

f (x) = I n (1 + x)

2 x + 2

2 x - 1

What is the critical f(x)=((x-1)^{2/3})/(x^2) ?
The critical f(x)=((x-1)^{2/3})/(x^2) is x=1,x= 3/2