What is the critical f(x)=(2x)/(x^2-25) ?

The critical f(x)=(2x)/(x^2-25) is None

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critical f(x)=(2x)/(x^2-25)

critical points

f (x) = \frac{2 x}{x ^{2} - 25}

None

Solution steps

\frac{2 x}{x ^{2} - 25}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = 5

Identify critical points not in

f (x)

domain

Domain of

\frac{2 x}{x ^{2} - 25} : x < - 5 or - 5 < x < 5 or x > 5

\frac{2 x}{x ^{2} - 25}

is not defined at

x = - 5, x = 5

, therefore:

None

f (x, y) = x^{2} - \frac{y ^{3}}{3} - \frac{x ^{2} \cdot y}{2} + 6 y

P (x, y) = 5 x^{3} + y^{2} - 3 x^{3} y^{2}

f (x) = x^{4} e^{- 5 x}

\frac{3 x}{x ^{2} - 36}

f (x) = 2 x^{2} + 4 x + 4

What is the critical f(x)=(2x)/(x^2-25) ?
The critical f(x)=(2x)/(x^2-25) is None