What is the critical f(x)=(-18x)/((x^2-9)^2) ?

The critical f(x)=(-18x)/((x^2-9)^2) is None

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critical f(x)=(-18x)/((x^2-9)^2)

critical points

f (x) = \frac{- 18 x}{( x ^{2} - 9 ) ^{2}}

None

Solution steps

\frac{- 18 x}{( x ^{2} - 9 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{- 18 x}{( x ^{2} - 9 ) ^{2}} : x < - 3 or - 3 < x < 3 or x > 3

\frac{- 18 x}{( x ^{2} - 9 ) ^{2}}

is not defined at

x = - 3, x = 3

, therefore:

None

f (x) = x 11 - x

x^{3} (x - 2)^{2}

f (x) = x^{3} - 6 x^{2} + 11

x e^{- 9 x}

f (x) = (x - 3) e^{x}

What is the critical f(x)=(-18x)/((x^2-9)^2) ?
The critical f(x)=(-18x)/((x^2-9)^2) is None