What is the critical f(x,y)=3x^4+3y^4-xy ?

The critical f(x,y)=3x^4+3y^4-xy is (0,0),(-1/(2sqrt(3)),-1/(2sqrt(3))),(1/(2sqrt(3)), 1/(2sqrt(3)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x,y)=3x^4+3y^4-xy

critical points

f (x, y) = 3 x^{4} + 3 y^{4} - x y

(0, 0), (- \frac{1}{2 3}, - \frac{1}{2 3}), (\frac{1}{2 3}, \frac{1}{2 3})

Solution steps

3 x^{4} + 3 y^{4} - x y

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (- \frac{1}{2 3}, - \frac{1}{2 3}), (\frac{1}{2 3}, \frac{1}{2 3})

f (x) = (x^{2} + 1 x + 2) e^{x - 2}

\frac{y - 3}{y ^{2} - 3 y + 9}

f (x) = x^{\frac{3}{4}} - x^{\frac{1}{4}}

\frac{( x - 1 )}{x ^{2}}

2 x^{3} + 5 x^{2} + 2 x

What is the critical f(x,y)=3x^4+3y^4-xy ?
The critical f(x,y)=3x^4+3y^4-xy is (0,0),(-1/(2sqrt(3)),-1/(2sqrt(3))),(1/(2sqrt(3)), 1/(2sqrt(3)))