What is the critical f(x)= x/(x^2+49) ?

The critical f(x)= x/(x^2+49) is x=-7,x=7

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critical f(x)= x/(x^2+49)

critical points

f (x) = \frac{x}{x ^{2} + 49}

x = - 7, x = 7

Solution steps

\frac{x}{x ^{2} + 49}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 7, x = 7

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 49} : - \infty < x < \infty

All critical points are in domain

x = - 7, x = 7

f (x) = \frac{8}{x ^{2} + 64}

\frac{1}{x ^{2} - 1}

x^{4} - 2 x^{2}

f (x) = 3 x + \frac{2}{x + 5}

f (x) = (2 x - 1) x^{\frac{2}{3}}

What is the critical f(x)= x/(x^2+49) ?
The critical f(x)= x/(x^2+49) is x=-7,x=7