What is the critical y=(x^2)/(x+1) ?

The critical y=(x^2)/(x+1) is x=-2,x=0

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critical y=(x^2)/(x+1)

critical points

y = \frac{x ^{2}}{x + 1}

x = - 2, x = 0

Solution steps

\frac{x ^{2}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x + 1} : x < - 1 or x > - 1

\frac{x ^{2}}{x + 1}

is not defined at

x = - 1

, therefore:

x = - 2, x = 0

f (x) = x^{3} - 9 x^{2} + 24 x + 5

y = I n (x - 1) + e^{x^{2} - 3} + (x^{2} - 4)^{\frac{5}{3}}

f (x) = \frac{2 ( x - 2 ) ^{2}}{e ^{x - 2}} + 1

f (x, y) = x^{3} + y^{2}

f (x, y) = 5 y e^{x} - 6 e^{y}