What is the critical f(x)= x/(x^2+14x+48) ?

The critical f(x)= x/(x^2+14x+48) is x=-4sqrt(3),x=4sqrt(3)

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critical f(x)= x/(x^2+14x+48)

critical points

f (x) = \frac{x}{x ^{2} + 14 x + 48}

x = - 43, x = 43

Solution steps

\frac{x}{x ^{2} + 14 x + 48}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 43, x = 43, x = - 8, x = - 6

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 14 x + 48} : x < - 8 or - 8 < x < - 6 or x > - 6

\frac{x}{x ^{2} + 14 x + 48}

is not defined at

x = - 8, x = - 6

, therefore:

x = - 43, x = 43

f (x) = (\frac{x - 2}{( x ^{2} - x + 1 ) ^{2}})

f (x) = 3 x^{2} - 5 x - 1

f (x) = \frac{5}{( 1 - 2 x ) ^{2}}

f (x) = x^{3} - \frac{3}{2} x^{2} - 6 x + 1

f (x) = - 2 x^{2} + 4 x + 6

What is the critical f(x)= x/(x^2+14x+48) ?
The critical f(x)= x/(x^2+14x+48) is x=-4sqrt(3),x=4sqrt(3)