critical f(x)=2x^3+3x^2-36x+4

解答

临界点

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 4

x = - 3, x = 2

求解步骤

2 x^{3} + 3 x^{2} - 36 x + 4

找到

f^{'} (x)

等于零或无定义的点

x = - 3, x = 2

确定不在

f (x)

定义域内的临界点

2 x^{3} + 3 x^{2} - 36 x + 4

的定义域

: - \infty < x < \infty

所有临界点均在定义域内

x = - 3, x = 2

3 x^{4} - 4 x^{3} - 12 x + 1

f (x) = \frac{( 2 x - 1 )}{x ^{2} - 4 x - 5}

f (x, y) = 2 x^{2} + y^{4} - 2 x^{2} y^{2} + 3

F (t) = 2 t \frac{2}{3} + t \frac{5}{3}

f (x) = 7 (x - 2)^{\frac{2}{3}}