What is the domain of 1/(-10(\frac{1){-5x-6}+3)} ?

The domain of 1/(-10(\frac{1){-5x-6}+3)} is x -17/15

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domain of 1/(-10(\frac{1){-5x-6}+3)}

domain

\frac{1}{- 10 ( \frac{1}{- 5 x - 6} + 3 )}

x < - \frac{6}{5} or - \frac{6}{5} < x < - \frac{17}{15} or x > - \frac{17}{15}

Interval Notation

(- \infty, - \frac{6}{5}) \cup (- \frac{6}{5}, - \frac{17}{15}) \cup (- \frac{17}{15}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{17}{15}, x = - \frac{6}{5}

The function domain

x < - \frac{6}{5} or - \frac{6}{5} < x < - \frac{17}{15} or x > - \frac{17}{15}

f (x) = 2 1 - 16 x^{2} + 10

f (x) = \frac{- 6 x ^{2} - 7 x + 1}{2 x + 3}

f (x) = 2^{x} + 1

f (x) = \frac{x}{ln ( x )}

\frac{4}{t ^{2} - 9}

What is the domain of 1/(-10(\frac{1){-5x-6}+3)} ?
The domain of 1/(-10(\frac{1){-5x-6}+3)} is x<-6/5 \lor-6/5 <x<-17/15 \lor x>-17/15