What is the critical f(x)=(x-6)e^{-3x} ?

The critical f(x)=(x-6)e^{-3x} is x= 19/3

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critical f(x)=(x-6)e^{-3x}

critical points

f (x) = (x - 6) e^{- 3 x}

x = \frac{19}{3}

Solution steps

(x - 6) e^{- 3 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{19}{3}

Identify critical points not in

f (x)

domain

Domain of

(x - 6) e^{- 3 x} : - \infty < x < \infty

All critical points are in domain

x = \frac{19}{3}

y = 2 x^{2} + 3 x + 5

f (x, y) = x^{2} + y^{2} + \frac{1}{x ^{2} y ^{2}}

f (x) = x^{\frac{2}{3}} (x - 1)

f (x) = \frac{1}{7} x^{7} - a^{6} x

(x - 1)^{2} (x + 2)

What is the critical f(x)=(x-6)e^{-3x} ?
The critical f(x)=(x-6)e^{-3x} is x= 19/3