What is the critical f(x)=(x^2-1)/(x^3) ?

The critical f(x)=(x^2-1)/(x^3) is x=-sqrt(3),x=sqrt(3)

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critical f(x)=(x^2-1)/(x^3)

critical points

f (x) = \frac{x ^{2} - 1}{x ^{3}}

x = - 3, x = 3

Solution steps

\frac{x ^{2} - 1}{x ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 1}{x ^{3}} : x < 0 or x > 0

\frac{x ^{2} - 1}{x ^{3}}

is not defined at

x = 0

, therefore:

x = - 3, x = 3

f (x) = (x^{2} - 25)^{7}

f (x) = 2 x^{3} - 24 x

f (x) = \frac{( y - 5 )}{y ^{2} - 3 y + 15}

x^{\frac{4}{5}} (x - 1)^{2}

f (x) = \frac{1}{2} x^{2} e^{- x}

What is the critical f(x)=(x^2-1)/(x^3) ?
The critical f(x)=(x^2-1)/(x^3) is x=-sqrt(3),x=sqrt(3)