What is the critical 4x^3-x^2-4x+3 ?

The critical 4x^3-x^2-4x+3 is x=-1/2 ,x= 2/3

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critical 4x^3-x^2-4x+3

critical points

4 x^{3} - x^{2} - 4 x + 3

x = - \frac{1}{2}, x = \frac{2}{3}

Solution steps

4 x^{3} - x^{2} - 4 x + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} - x^{2} - 4 x + 3 : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}, x = \frac{2}{3}

f (x) = \frac{1}{2 x - 1}

f (x) = x^{6} e^{- 7 x}

f (x) = 6 x^{2} + 6 x - 36

f (x) = \frac{x ^{2}}{2} - 6 ln (x) + x

3 x^{2} - 18 x + 24

What is the critical 4x^3-x^2-4x+3 ?
The critical 4x^3-x^2-4x+3 is x=-1/2 ,x= 2/3