What is the critical f(x)=(-2x^2+5x-1)/(2x-1) ?

The critical f(x)=(-2x^2+5x-1)/(2x-1) is None

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critical f(x)=(-2x^2+5x-1)/(2x-1)

critical points

f (x) = \frac{- 2 x ^{2} + 5 x - 1}{2 x - 1}

None

Solution steps

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1} : x < \frac{1}{2} or x > \frac{1}{2}

\frac{- 2 x ^{2} + 5 x - 1}{2 x - 1}

is not defined at

x = \frac{1}{2}

, therefore:

None

f (x) = \frac{( x ^{2} - 4 )}{x ^{2} - 1}

f (x) = 2 x e^{- x} - x^{2} e^{- x}

f (x) = (11 - 6 x) e^{x}

f (x) = 3 x^{4} + 20 x^{3} - 36 x^{2} + 7

f (x) = 3 x^{5} - 5 x^{3} + 5

What is the critical f(x)=(-2x^2+5x-1)/(2x-1) ?
The critical f(x)=(-2x^2+5x-1)/(2x-1) is None