What is the critical f(x)=sqrt(|x|)+x/6 ?

The critical f(x)=sqrt(|x|)+x/6 is x=-9,x=0

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critical f(x)=sqrt(|x|)+x/6

critical points

f (x) = ∣ x ∣ + \frac{x}{6}

x = - 9, x = 0

Solution steps

∣ x ∣ + \frac{x}{6}

Absolute value functions are piecewise functions

Find the function intervals:

x < 0, x = 0, x > 0

Evaluate the function behavior for each interval

Find where

f^{'} (x)

is equal to zero or undefined

x = - 9, x = 0

f (x) = \frac{- x ^{2} + 1}{( x ^{2} + 1 ) ^{2}}

f (x) = 3 - (x + 1)^{3}

f (x) = \frac{1}{4} x^{4} + \frac{4}{3} x^{3} + 2 x^{2}

f (x) = \frac{- 4 x}{x - 8}

\frac{x}{x ^{2} + 49}

What is the critical f(x)=sqrt(|x|)+x/6 ?
The critical f(x)=sqrt(|x|)+x/6 is x=-9,x=0