What is the critical f(x)=((x^2-16))/((2x^2+7x-15)) ?

The critical f(x)=((x^2-16))/((2x^2+7x-15)) is None

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critical f(x)=((x^2-16))/((2x^2+7x-15))

critical points

f (x) = \frac{( x ^{2} - 16 )}{( 2 x ^{2} + 7 x - 15 )}

None

Solution steps

\frac{x ^{2} - 16}{2 x ^{2} + 7 x - 15}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 16}{2 x ^{2} + 7 x - 15} : x < - 5 or - 5 < x < \frac{3}{2} or x > \frac{3}{2}

\frac{x ^{2} - 16}{2 x ^{2} + 7 x - 15}

is not defined at

x = - 5, x = \frac{3}{2}

, therefore:

None

f (x) = x^{2} - 64

x e^{- x^{2} - y^{2}}

\frac{t ^{2}}{t - 2}

4 + x e^{- \frac{1}{2} x}

3 x^{2} - 6 x + 24

What is the critical f(x)=((x^2-16))/((2x^2+7x-15)) ?
The critical f(x)=((x^2-16))/((2x^2+7x-15)) is None