en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical x/(2x^2-1)

Solution

critical points

\frac{x}{2 x ^{2} - 1}

Solution

None

Solution steps

\frac{x}{2 x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{2 x ^{2} - 1} : x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{1}{2} or x > \frac{1}{2}

\frac{x}{2 x ^{2} - 1}

is not defined at

x = - \frac{1}{2}, x = \frac{1}{2}

, therefore:

None

Popular Examples

critical f(x)=(x-1)^3+1 critical points

f (x) = (x - 1)^{3} + 1

critical y= 1/(x^2-9)critical points

y = \frac{1}{x ^{2} - 9}

critical 8x^2ln(x)critical points

8 x^{2} ln (x)

critical y=cos(2x)-x critical points

y = cos (2 x) - x

critical f(x)=x^2+xy+3x+2y+5 critical points

f (x) = x^{2} + x y + 3 x + 2 y + 5

Frequently Asked Questions (FAQ)

What is the critical x/(2x^2-1) ?
The critical x/(2x^2-1) is None